In Young's double slit experiment, how many maxima can be obtained on a screen (including central maxima). If `d=(5lambda)/2` (where `lambda` is the wavelength of light)?

Answer

5

Explanation

In YDSE path difference. `Delta x=d sin theta` For maxima, `Delta x=n lambda,` where
`n=0, pm 1, pm 2.....` `(5 lambda)/(2) sin theta = n lambda("given that d"=(5 lambda)/(2))`
`implies sin theta=(2n)/(5)......(i) ` Since, `-1 le sin theta le 1 "From"(i)implies -1 le 2n//5 le 1`
So, `-(5)/(2) le n le (5)/(2)` So, possible values of n are -2,-1, 0,1,2 Thus a total of 5 maximas will be obtained.