A positive charge q is given to each plate of a parallel plate air capacitor having plate area A and plate separation d, then

Options

A. since both the plates are identially charged, therefore, capacitance become equal to zero
B. energy stored in the space between the capacitor plates is equal to `(q^(2))/(epsilon_(0)A^(2))`
C. no charge appears on inner surface of the plates
D. potential difference between the plates is equal to `(2qd)/(epsilon_(0)A)`

Answer

C

Explanation

Capacitance does not depend on charge on it `C=(epsilon_(0)4)/d`

In final charge distributioni, Charge on outer plates `q_(1)+q_(4)=q` and inner plates `q_(2)=q_(3)=0`
As charge on inner plates are zero so there is no field between the plates adn no potential difference and no energy is stored.