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The ratio of the magnetic field at the c...

The ratio of the magnetic field at the centre of a current carrying circular coil to its magnetic moment is x. If the current and radius both are doubled the new ratio will become

A

`2x`

B

`4x`

C

`x//4`

D

`x//8`

Text Solution

Verified by Experts

The correct Answer is:
D

`x=B/M=((mu_(0)i)/(2r))(1/(ipir^(2)))"or" x prop 1/(r^(3))`
i.e. will become `x/8` when radius and current both are doubled.
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