A massless rod BD of length l is suspended by two identical massless strings AB and CD of equal lengths. A block of mass m is suspended from a point P such that BP is equal to x. If the fundamental frequency of the left wire is twice the fundamental frequency of therigh wire, then the value of `l/x` is

Answer

`5`

Explanation

`fprop v prop sqrt(T)`
`f_(AB)=2f_(CD)`
`:.T_(AB)=4T_(CD)`……..i
Further `Sigmatau_(p)=0`
`:.T_(AB)=(x)=T_(CD)(l-x)`
or `4x=l-x`
`(T_(AB)=4T_(CD))`
or `x=l//5`
`impliesl/x=5`