The potential energy of a particle under a conservative force is given by `U ( x) = ( x^(2) -3x)` J. The equilibrium position of the particle is at

Answer

`1.5`

Explanation

`U(x)=(x^(2)-3x)J`
For a conservative field force
`F=-(dU)/(dx)`
`:.F=-d/(dx)(x^(2)-3x)=-(2x-3)`
`=-2x+3`
At equilibrium position F=0
`-2x+3=0impliesx=3/2m=1.5m`