In young's double slit experiment relative intensity at a point on the screen may be defined as ratio of intensity at that point to the maximum intensity on the screen. Light of wavelength `7500overset(@)A` A passing through a double slit, produces interference pattern of relative intensity variation as shown in Fig. `theta` on horizontal axis represents the angular position of a point on the screen

(a) Find separation d between the slits.
(b) Find the ratio of amplitudes of the two waves producing interference pattern on the screen.

Answer

`2`

Explanation

`(I_("max"))/(I_("min"))=((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)`
`9=((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)`
`implies(a_(1)+a_(2))/(a_(1)-a_(2))=3`
`implies(a_(1))/(a_(2))=2/1`