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Resistance of 100 Omega and 200 Omega a...

Resistance of `100 Omega ` and `200 Omega` are connected in series with 220 V mains. When a voltmeter of `1000 Omega` resistance is connected in parallel to`100 Omega` , then the reading of voltmeter is

A

`68.75V`

B

`6.87 V`

C

`584.5 V`

D

`58.75 V`

Text Solution

Verified by Experts

The correct Answer is:
A
Use Kirchoff.s voltage law in the loops to solve the problem, and also use OHM.s law V = iR for the given system, where i&R represents required current and resistance respectively.

`R_(eq)=(3200)/(11) Omega`
`V=(220)/(((3200)/(11)))xx(1000)/(11)=(2200)/(2)=68.75V`
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