A galvanometer of resistance `25Omega` is connected to a battery of 2V along with a resistance of `3000Omega`. In this case, a full - scale deflection of 30 units is obtained in the galvanometer. In order or reduce this deflection to 10 units, how much more resistance `("in "Omega)` should be added to the circuit in series?

Answer

6050

Explanation

The deflection in a galvanometer is directly proportional to the current.
First case:
`30x=(2)/(25+3000)`
Second case :
`10x=(2)/(25+3000+R)`