When the forwward bias voltage of a diode is changed from `0.6` V to `0.7` V the current changes from 5 mA to 15 mA. Then its forward bias resistance is

Answer

10

Explanation

The forward biased resistance of a diode is
`R=(DeltaB)/(DeltaI)=(0.7-0.6)/((15-5)xx10^(-3))`
`R=(0.1)/(10xx10^(-3))=10 Omega`