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A flux of 10^(-3)Wb passes through a str...

A flux of `10^(-3)Wb` passes through a strip having an area `A = 0.02m^(2)`. The plane of the strip is at an angle of `60^(@)` to be direction of a uniform field B. The value of B is

A

0.1T

B

0.058T

C

4.0mT

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B
As the angle between field and plane is `60^(@)` therefore angle between area vector and magnetic field is
`theta=30^(@)`
magnetic flux through the strip is
`phi=BAcos theta`
`10^(-3)=B(0.02)cos 30^(@)`
`B=(10^(-3))/((0.02)((sqrt(3))/2))`
`B=0.058t`
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Knowledge Check

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