A flux of `10^(-3)Wb` passes through a strip having an area `A = 0.02m^(2)`. The plane of the strip is at an angle of `60^(@)` to be direction of a uniform field B. The value of B is

Options

A. 0.1T
B. 0.058T
C. 4.0mT
D. None of the above

Answer

B

Explanation

As the angle between field and plane is `60^(@)` therefore angle between area vector and magnetic field is
`theta=30^(@)`
magnetic flux through the strip is
`phi=BAcos theta`
`10^(-3)=B(0.02)cos 30^(@)`
`B=(10^(-3))/((0.02)((sqrt(3))/2))`
`B=0.058t`