An air bubble of radius 1 mm is located at a depth of 20 cm below water level. The excess pressure inside the bubble above the atmospheric pressure is [Given, the surface tension of water is `"0.075 Nm"^(-1)` and density is `"1000 kg m"^(-3)`]

Options

A. 2110Pa
B. 2210Pa
C. 2260Pa
D. 2310Pa

Answer

A

Explanation

Let the atmospheric pressure be `P_(0)`
Pressure just outside the bubble
`P=P_(0)+h rho g`
Pressure of air inside the bubble
`P_("in")=R+(2 sigma)/r, sigma` is surface tension
`P_("in")=P_(0)+h rho g+(2sigma)/r`
`:.P.-P_(0)=1/5xx1000xx9.8+(2xx0.075)/(1xx10^(-3))`
`=1960+150`
`=2110`Pa