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The Lucknow-Indore express without its r...

The Lucknow-Indore express without its rake can go 24 km an hour, and the speed is diminished by a quantity that varies as the square root of the number of wagon attached. Id it is known that with four wagons its speed is `20 km"/"h`, the greatest number of wagons with which the engine can just move is

A

144

B

140

C

143

D

124

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information provided and derive the necessary equations. ### Step 1: Define the variables Let: - \( n \) = number of wagons attached to the train. - \( k \) = constant that represents the rate at which speed decreases with the increase in the number of wagons. ### Step 2: Establish the speed equation The speed of the train without any wagons is given as 24 km/h. The speed decreases by an amount that varies as the square root of the number of wagons. Therefore, we can express the speed \( S \) as: \[ S = 24 - k \sqrt{n} \] ### Step 3: Use the given condition We know that with 4 wagons, the speed is 20 km/h. We can substitute \( n = 4 \) and \( S = 20 \) into the equation to find \( k \): \[ 20 = 24 - k \sqrt{4} \] \[ 20 = 24 - 2k \] \[ 2k = 24 - 20 \] \[ 2k = 4 \] \[ k = 2 \] ### Step 4: Substitute \( k \) back into the speed equation Now we substitute \( k \) back into the speed equation: \[ S = 24 - 2 \sqrt{n} \] ### Step 5: Find when the speed is zero To find the maximum number of wagons \( n \) that the engine can just move, we set the speed \( S \) to 0: \[ 0 = 24 - 2 \sqrt{n} \] \[ 2 \sqrt{n} = 24 \] \[ \sqrt{n} = 12 \] \[ n = 12^2 = 144 \] ### Step 6: Determine the greatest number of wagons Since the engine can just move when the speed is 0 with 144 wagons, the greatest number of wagons with which the engine can still move is: \[ n = 144 - 1 = 143 \] ### Final Answer The greatest number of wagons with which the engine can just move is **143**. ---
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