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A bucket contains a mixture of two liqui...

A bucket contains a mixture of two liquids A and B in the proportion `7 : 5`. If 9 litres of mixture is replaced by 9 liters of liquid B, then the ratio of the two liquids becomes `7 : 9`. How much of the liquid A was there in the bucket ?

A

21 liters

B

23 liters

C

25 liters

D

27 liters

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break down the information given and the operations we need to perform. ### Step 1: Understand the initial ratio The initial ratio of liquids A and B is given as \( 7:5 \). This means that for every 12 parts of the mixture, 7 parts are liquid A and 5 parts are liquid B. ### Step 2: Define the total volume of the mixture Let the total volume of the mixture be \( x \) liters. Then the volumes of A and B can be expressed as: - Volume of A = \( \frac{7}{12}x \) - Volume of B = \( \frac{5}{12}x \) ### Step 3: Calculate the volumes after removing 9 liters of the mixture When we remove 9 liters of the mixture, we are removing both liquids A and B in the same ratio \( 7:5 \). The volume of A removed can be calculated as: - Volume of A removed = \( \frac{7}{12} \times 9 = \frac{63}{12} = 5.25 \) liters - Volume of B removed = \( \frac{5}{12} \times 9 = \frac{45}{12} = 3.75 \) liters ### Step 4: Update the volumes of A and B After removing 9 liters of the mixture, the new volumes of A and B will be: - New volume of A = \( \frac{7}{12}x - 5.25 \) - New volume of B = \( \frac{5}{12}x - 3.75 \) ### Step 5: Add 9 liters of liquid B Now, we add 9 liters of liquid B to the mixture. Therefore, the new volume of B becomes: - New volume of B = \( \left(\frac{5}{12}x - 3.75\right) + 9 = \frac{5}{12}x + 5.25 \) ### Step 6: Set up the new ratio According to the problem, after adding 9 liters of B, the new ratio of A to B becomes \( 7:9 \). Thus, we can set up the equation: \[ \frac{\frac{7}{12}x - 5.25}{\frac{5}{12}x + 5.25} = \frac{7}{9} \] ### Step 7: Cross-multiply to solve for \( x \) Cross-multiplying gives: \[ 9\left(\frac{7}{12}x - 5.25\right) = 7\left(\frac{5}{12}x + 5.25\right) \] Expanding both sides: \[ \frac{63}{12}x - 47.25 = \frac{35}{12}x + 36.75 \] ### Step 8: Combine like terms Rearranging gives: \[ \frac{63}{12}x - \frac{35}{12}x = 47.25 + 36.75 \] \[ \frac{28}{12}x = 84 \] \[ x = \frac{84 \times 12}{28} = 36 \text{ liters} \] ### Step 9: Calculate the volume of liquid A Now that we have the total volume of the mixture, we can find the volume of liquid A: \[ \text{Volume of A} = \frac{7}{12} \times 36 = 21 \text{ liters} \] ### Final Answer The amount of liquid A in the bucket is **21 liters**. ---
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