Home
Class 14
MATHS
The ratio of squares of first n natural ...

The ratio of squares of first n natural numbers to square of sum of first n natural numbers is `17 : 325`. The value of n is :

A

15

B

25

C

35

D

30

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( n \) given the ratio of the square of the sum of the first \( n \) natural numbers to the square of the sum of the first \( n \) natural numbers is \( 17 : 325 \). ### Step-by-step Solution: 1. **Understanding the formulas**: - The sum of the first \( n \) natural numbers is given by: \[ S_n = \frac{n(n + 1)}{2} \] - The sum of the squares of the first \( n \) natural numbers is given by: \[ S_{n, \text{squares}} = \frac{n(n + 1)(2n + 1)}{6} \] 2. **Setting up the ratio**: - We need to find the ratio of the sum of squares to the square of the sum: \[ \frac{S_{n, \text{squares}}}{(S_n)^2} = \frac{\frac{n(n + 1)(2n + 1)}{6}}{\left(\frac{n(n + 1)}{2}\right)^2} \] 3. **Simplifying the expression**: - First, calculate \( (S_n)^2 \): \[ (S_n)^2 = \left(\frac{n(n + 1)}{2}\right)^2 = \frac{n^2(n + 1)^2}{4} \] - Now substituting into the ratio: \[ \frac{\frac{n(n + 1)(2n + 1)}{6}}{\frac{n^2(n + 1)^2}{4}} = \frac{n(n + 1)(2n + 1)}{6} \cdot \frac{4}{n^2(n + 1)^2} \] - This simplifies to: \[ \frac{4(2n + 1)}{6n(n + 1)} = \frac{2(2n + 1)}{3n(n + 1)} \] 4. **Setting the ratio equal to \( \frac{17}{325} \)**: - We set up the equation: \[ \frac{2(2n + 1)}{3n(n + 1)} = \frac{17}{325} \] 5. **Cross-multiplying to eliminate the fraction**: - Cross-multiplying gives: \[ 2(2n + 1) \cdot 325 = 17 \cdot 3n(n + 1) \] - This simplifies to: \[ 650(2n + 1) = 51n(n + 1) \] 6. **Expanding both sides**: - Expanding gives: \[ 1300n + 650 = 51n^2 + 51n \] 7. **Rearranging the equation**: - Rearranging leads to: \[ 51n^2 - 1249n - 650 = 0 \] 8. **Using the quadratic formula**: - We can use the quadratic formula \( n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): - Here, \( a = 51 \), \( b = -1249 \), and \( c = -650 \). - Calculate the discriminant: \[ b^2 - 4ac = (-1249)^2 - 4 \cdot 51 \cdot (-650) \] - Solve for \( n \). 9. **Finding the value of \( n \)**: - After calculating, we find that \( n = 25 \). ### Final Answer: The value of \( n \) is \( 25 \).
Promotional Banner

Similar Questions

Explore conceptually related problems

Sum of cube of first n natural number

Find sum of first n natural numbers.

The sum of squares of first ten natural numbers is :

The sum of first n odd natural numbers is

Find the sum of first n natural numbers.

What is the sum of first n natural numbers ?

Find the sum of first n natural numbers.

Find the sum of first n natural numbers.