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Find the length of a rectangle whose dia...

Find the length of a rectangle whose diagonal and area is 25 cm and 168 `cm^2` respectively :

A

31 cm

B

24 cm

C

17 cm

D

9 cm

Text Solution

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The correct Answer is:
To find the length of the rectangle given its diagonal and area, we can follow these steps: ### Step 1: Define Variables Let the length of the rectangle be \( L \) and the breadth be \( B \). ### Step 2: Use the Diagonal Formula The diagonal \( D \) of a rectangle can be expressed using the Pythagorean theorem: \[ D = \sqrt{L^2 + B^2} \] Given that the diagonal is 25 cm, we can write: \[ \sqrt{L^2 + B^2} = 25 \] Squaring both sides gives us: \[ L^2 + B^2 = 625 \quad \text{(Equation 1)} \] ### Step 3: Use the Area Formula The area \( A \) of a rectangle is given by: \[ A = L \times B \] Given that the area is 168 cm², we can write: \[ L \times B = 168 \quad \text{(Equation 2)} \] ### Step 4: Express \( B \) in Terms of \( L \) From Equation 2, we can express \( B \) as: \[ B = \frac{168}{L} \] ### Step 5: Substitute \( B \) in Equation 1 Substituting \( B \) in Equation 1: \[ L^2 + \left(\frac{168}{L}\right)^2 = 625 \] This simplifies to: \[ L^2 + \frac{28224}{L^2} = 625 \] ### Step 6: Multiply through by \( L^2 \) to eliminate the fraction Multiplying through by \( L^2 \) gives: \[ L^4 - 625L^2 + 28224 = 0 \] Let \( x = L^2 \). Then the equation becomes: \[ x^2 - 625x + 28224 = 0 \] ### Step 7: Solve the Quadratic Equation Using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): \[ x = \frac{625 \pm \sqrt{625^2 - 4 \cdot 1 \cdot 28224}}{2 \cdot 1} \] Calculating the discriminant: \[ 625^2 = 390625 \] \[ 4 \cdot 28224 = 112896 \] \[ 625^2 - 4 \cdot 28224 = 390625 - 112896 = 277729 \] Now, taking the square root: \[ \sqrt{277729} = 527 \] Thus, we have: \[ x = \frac{625 \pm 527}{2} \] Calculating the two possible values: 1. \( x = \frac{1152}{2} = 576 \) 2. \( x = \frac{98}{2} = 49 \) ### Step 8: Find \( L \) from \( x \) Since \( x = L^2 \): 1. If \( L^2 = 576 \), then \( L = 24 \) (since length must be positive). 2. If \( L^2 = 49 \), then \( L = 7 \). ### Step 9: Determine the Corresponding \( B \) Using \( L = 24 \): \[ B = \frac{168}{24} = 7 \] Using \( L = 7 \): \[ B = \frac{168}{7} = 24 \] ### Conclusion The length of the rectangle is \( L = 24 \) cm (the other dimension is the breadth \( B = 7 \) cm).
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