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A bag contains 5 red balls, 8 white ball...

A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black balls. If one ball is drawn at random, find the probability that it is not green

A

`1/6`

B

`5/6`

C

`5/8`

D

`1/2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability that a ball drawn from the bag is not green, we can follow these steps: ### Step 1: Determine the total number of balls in the bag. - Count the number of each color of balls: - Red balls = 5 - White balls = 8 - Green balls = 4 - Black balls = 7 **Total number of balls = Red + White + Green + Black** \[ \text{Total} = 5 + 8 + 4 + 7 = 24 \] ### Step 2: Determine the number of balls that are not green. - Since there are 4 green balls, we can find the number of balls that are not green by subtracting the number of green balls from the total number of balls. **Number of not green balls = Total balls - Green balls** \[ \text{Not green} = 24 - 4 = 20 \] ### Step 3: Calculate the probability of drawing a ball that is not green. - Probability is calculated using the formula: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] - In this case, the number of favorable outcomes is the number of not green balls, and the total number of outcomes is the total number of balls. **Probability of not green = \(\frac{\text{Not green}}{\text{Total}}\)** \[ \text{Probability} = \frac{20}{24} \] ### Step 4: Simplify the fraction. - We can simplify \(\frac{20}{24}\) by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 4. \[ \frac{20 \div 4}{24 \div 4} = \frac{5}{6} \] ### Final Answer: The probability that the ball drawn is not green is \(\frac{5}{6}\). ---
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