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From a circular piece of cardboard of ra...

From a circular piece of cardboard of radius 3 cm, two sectors of `40^@` each have been cut off. The area of the remaining portion is : `(use pi = 22/7)`

A

11 `cm^2`

B

22 `cm^2`

C

33 `cm^2`

D

44 `cm^2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the remaining portion of the circular piece of cardboard after cutting off two sectors of 40 degrees each, we can follow these steps: ### Step 1: Calculate the total area of the circle The formula for the area of a circle is: \[ \text{Area} = \pi r^2 \] Given that the radius \( r = 3 \) cm and using \( \pi = \frac{22}{7} \): \[ \text{Area} = \frac{22}{7} \times (3)^2 \] \[ = \frac{22}{7} \times 9 \] \[ = \frac{198}{7} \text{ cm}^2 \] ### Step 2: Calculate the total angle of the sectors cut off Each sector has an angle of \( 40^\circ \), and since two sectors are cut off: \[ \text{Total angle of sectors} = 40^\circ + 40^\circ = 80^\circ \] ### Step 3: Calculate the area of the sectors cut off Using the formula for the area of a sector: \[ \text{Area of sector} = \frac{\theta}{360} \times \pi r^2 \] For the total area of the two sectors: \[ \text{Area of sectors} = \frac{80}{360} \times \frac{22}{7} \times (3)^2 \] \[ = \frac{80}{360} \times \frac{22}{7} \times 9 \] \[ = \frac{2}{9} \times \frac{22}{7} \times 9 \] \[ = \frac{2 \times 22}{7} = \frac{44}{7} \text{ cm}^2 \] ### Step 4: Calculate the area of the remaining portion Now, subtract the area of the sectors from the total area of the circle: \[ \text{Area of remaining portion} = \text{Total area} - \text{Area of sectors} \] \[ = \frac{198}{7} - \frac{44}{7} \] \[ = \frac{198 - 44}{7} = \frac{154}{7} \text{ cm}^2 \] ### Step 5: Simplify the area of the remaining portion Calculating \( \frac{154}{7} \): \[ = 22 \text{ cm}^2 \] ### Final Answer The area of the remaining portion is \( 22 \text{ cm}^2 \). ---
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