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If for a triangle, the radius of the cir...

If for a triangle, the radius of the circumcircle is double the radius of the inscribed circle (incircle), then which one of the following is correct?

A

The triangle is a right angled.

B

The triangle is an isosceles.

C

The triangle is an equilateral.

D

None of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the relationship between the circumradius (R) and the inradius (r) of a triangle, given that R = 2r. ### Step 1: Understanding the Definitions - **Circumradius (R)**: The radius of the circumcircle of a triangle, which is the circle that passes through all three vertices of the triangle. - **Inradius (r)**: The radius of the incircle of a triangle, which is the circle that is tangent to all three sides of the triangle. ### Step 2: Formulas for R and r For any triangle: - The circumradius \( R \) is given by the formula: \[ R = \frac{abc}{4\Delta} \] where \( a, b, c \) are the lengths of the sides of the triangle and \( \Delta \) is the area of the triangle. - The inradius \( r \) is given by the formula: \[ r = \frac{\Delta}{s} \] where \( s \) is the semi-perimeter of the triangle, defined as \( s = \frac{a+b+c}{2} \). ### Step 3: Setting Up the Condition According to the problem, we have: \[ R = 2r \] Substituting the formulas for R and r, we get: \[ \frac{abc}{4\Delta} = 2 \cdot \frac{\Delta}{s} \] ### Step 4: Cross-Multiplying Cross-multiplying gives us: \[ abc \cdot s = 8\Delta^2 \] ### Step 5: Exploring the Triangle Types To find which type of triangle satisfies this condition, we can test specific types of triangles: 1. **Equilateral Triangle**: - For an equilateral triangle with side length \( a \): - Area \( \Delta = \frac{\sqrt{3}}{4} a^2 \) - Semi-perimeter \( s = \frac{3a}{2} \) - Circumradius \( R = \frac{a}{\sqrt{3}} \) - Inradius \( r = \frac{a}{2\sqrt{3}} \) Substituting these values into the condition \( R = 2r \): \[ \frac{a}{\sqrt{3}} = 2 \cdot \frac{a}{2\sqrt{3}} \Rightarrow \frac{a}{\sqrt{3}} = \frac{a}{\sqrt{3}} \text{ (True)} \] 2. **Isosceles Triangle**: - The relationship may not hold for all isosceles triangles, as the sides can vary. 3. **Right Triangle**: - The relationship also does not hold universally for right triangles. ### Step 6: Conclusion From the analysis, we find that the condition \( R = 2r \) holds true for equilateral triangles. Therefore, the correct answer is: **The triangle is equilateral.**
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