In a quadrilateral ABCD angleA+angleC is...

In a quadrilateral `ABCD angleA+angleC` is 2 times `angleB+angleD`. If `angleA=140^(@)angle D=60^(@)`, then `angleB`=

A

`60^@`

B

`80^@`

C

`90^@`

D

`120^@`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

In a quadrilateral ABCD, angleA + angleC = 180^(@) , then angleB + angleD is equal to

If angleACD is an exterior angle of DeltaABC . If angleACD=110^(@) and angleA=60^(@) , then angleB= ..........,

In triangleABC, angleA=76^(@), angleB=48^(@) , then find angleC=?

In triangleABC and trianglePQR, AB = PQ, angleA = angleP and angleB = angleQ . If angleA + angleC = 130^(@) , then angleQ = ..........

angleA and angleB are complementary angles. If angleA=x+20^(@) and angleB=x-10^(@) , find angleA and angleB .

In a triangleABC if angleA=72^(@) and angleB=63^(@) ,find angleC

In DeltaABC , if angleA=62^(@),angleB=28^(@) then find angleC

In a quadrilateral ABCD the linesegment bisecting angleC and angleD meet at E. Prove that angleA+angleB=2angleCED.

In the formula angleA+angleB+angleC=180^(@) , if angleA=90^(@) and angle B=55^(@) , then angleC= _______

In triangleABC , if angleA=45^(@), angleB=60^(@), angleC=75^(@) , then a:b:c =