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The perimeter of a triangle is 12 cm. If...

The perimeter of a triangle is 12 cm. If all the three sides have lengths (in cm), in integers, then how many such different triangles are possible?

A

2

B

3

C

4

D

5

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of different triangles with integer side lengths that have a perimeter of 12 cm, we can follow these steps: ### Step 1: Understand the Triangle Inequality The triangle inequality states that for any triangle with sides \(A\), \(B\), and \(C\): 1. \(A + B > C\) 2. \(A + C > B\) 3. \(B + C > A\) ### Step 2: Set Up the Equation Since the perimeter of the triangle is 12 cm, we can express this as: \[ A + B + C = 12 \] ### Step 3: Express One Side in Terms of the Others We can express \(C\) in terms of \(A\) and \(B\): \[ C = 12 - A - B \] ### Step 4: Apply the Triangle Inequality Now we substitute \(C\) into the triangle inequalities: 1. From \(A + B > C\): \[ A + B > 12 - A - B \] \[ 2A + 2B > 12 \] \[ A + B > 6 \] 2. From \(A + C > B\): \[ A + (12 - A - B) > B \] \[ 12 - B > B \] \[ 12 > 2B \] \[ B < 6 \] 3. From \(B + C > A\): \[ B + (12 - A - B) > A \] \[ 12 - A > A \] \[ 12 > 2A \] \[ A < 6 \] ### Step 5: Determine Possible Values From the inequalities, we have: - \(A + B > 6\) - \(A < 6\) - \(B < 6\) ### Step 6: List Possible Integer Combinations Now we can list the integer combinations of \(A\), \(B\), and \(C\) that satisfy these inequalities: 1. **If \(A = 1\)**: - \(B + C = 11\) (not possible since \(B\) and \(C\) must be less than 6) 2. **If \(A = 2\)**: - \(B + C = 10\) (not possible) 3. **If \(A = 3\)**: - \(B + C = 9\) (not possible) 4. **If \(A = 4\)**: - \(B + C = 8\) (not possible) 5. **If \(A = 5\)**: - \(B + C = 7\) (possible combinations: \(B = 5, C = 2\) or \(B = 4, C = 3\)) 6. **If \(A = 6\)**: - \(B + C = 6\) (possible combinations: \(B = 3, C = 3\)) ### Step 7: Valid Combinations From the above steps, the valid combinations that satisfy the triangle inequality and the perimeter condition are: 1. \(A = 5, B = 5, C = 2\) 2. \(A = 5, B = 4, C = 3\) 3. \(A = 4, B = 4, C = 4\) ### Conclusion Thus, the different triangles that can be formed with integer side lengths summing to 12 cm are: - \( (5, 5, 2) \) - \( (5, 4, 3) \) - \( (4, 4, 4) \) Therefore, the total number of different triangles possible is **3**.
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