Home
Class 14
MATHS
The sum of all interior angles of a poly...

The sum of all interior angles of a polygon is `1440^@`. The number of sides of the polygon is

A

9

B

10

C

12

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of sides of a polygon given that the sum of all interior angles is \(1440^\circ\), we can use the formula for the sum of interior angles of a polygon: \[ \text{Sum of interior angles} = (n - 2) \times 180^\circ \] where \(n\) is the number of sides of the polygon. ### Step 1: Set up the equation We know the sum of the interior angles is \(1440^\circ\). Therefore, we can set up the equation: \[ (n - 2) \times 180^\circ = 1440^\circ \] ### Step 2: Divide both sides by \(180^\circ\) To simplify the equation, divide both sides by \(180^\circ\): \[ n - 2 = \frac{1440^\circ}{180^\circ} \] ### Step 3: Calculate the right side Now, calculate \(\frac{1440}{180}\): \[ \frac{1440}{180} = 8 \] So, we have: \[ n - 2 = 8 \] ### Step 4: Solve for \(n\) Now, add \(2\) to both sides to solve for \(n\): \[ n = 8 + 2 = 10 \] ### Conclusion The number of sides of the polygon is \(10\).
Promotional Banner

Similar Questions

Explore conceptually related problems

The sum of the interior angles of a polygon is 1260^(@) . The number of sides of the polygon is :