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The sum of the present ages of father an...

The sum of the present ages of father and son is 68 years. 8 years ago, the ratio of their ages was `12 : 1`. The ratio of their ages after 4 years hence is:

A

`15 : 4`

B

`14 : 3`

C

`16 : 5`

D

`13 : 2`

Text Solution

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The correct Answer is:
To solve the problem step by step, let's define the variables and set up the equations based on the information provided. ### Step 1: Define the Variables Let: - \( x \) = present age of the father - \( y \) = present age of the son ### Step 2: Set Up the First Equation According to the problem, the sum of their present ages is 68 years: \[ x + y = 68 \quad \text{(Equation 1)} \] ### Step 3: Set Up the Second Equation The problem states that 8 years ago, the ratio of their ages was \( 12:1 \). Therefore, 8 years ago: - Father's age = \( x - 8 \) - Son's age = \( y - 8 \) The ratio can be expressed as: \[ \frac{x - 8}{y - 8} = \frac{12}{1} \] Cross-multiplying gives: \[ x - 8 = 12(y - 8) \] Expanding this, we get: \[ x - 8 = 12y - 96 \] Rearranging the equation, we have: \[ x - 12y = -88 \quad \text{(Equation 2)} \] ### Step 4: Solve the System of Equations Now we have two equations: 1. \( x + y = 68 \) 2. \( x - 12y = -88 \) We can solve these equations simultaneously. Let's express \( x \) from Equation 1: \[ x = 68 - y \] Now substitute \( x \) in Equation 2: \[ (68 - y) - 12y = -88 \] Simplifying this gives: \[ 68 - y - 12y = -88 \] \[ 68 - 13y = -88 \] \[ -13y = -88 - 68 \] \[ -13y = -156 \] \[ y = \frac{-156}{-13} = 12 \] ### Step 5: Find the Father's Age Now, substitute \( y \) back into Equation 1 to find \( x \): \[ x + 12 = 68 \] \[ x = 68 - 12 = 56 \] ### Step 6: Calculate Ages After 4 Years After 4 years, the ages will be: - Father's age = \( 56 + 4 = 60 \) - Son's age = \( 12 + 4 = 16 \) ### Step 7: Find the Ratio of Their Ages After 4 Years The ratio of their ages after 4 years is: \[ \frac{60}{16} = \frac{15}{4} \] ### Final Answer The ratio of their ages after 4 years hence is \( 15:4 \). ---
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