(R)-2-methyl-1-butanol has a specific rotation of "`+13.5^(@)`".The specific rotation of "2" - methyl-1-butanol containing "40%" of the (S)- enantiomer is

Let (+) tartaric acid has a specific rotation of +11.1 , Calculate the specific rotation of a mixture of 68%(+) tartaric acid and 32%(-) tartaric acid.

An organic compound P exists in two enantiomeric forms, which have specific optical rotation values [alpha] = +-100^(@) . The optical rotation of a mixture of these two enantiomers is -50^(@) . Calculate the percentage of that enantiomer which is in lower concentration in the mixture.

Pure (R) Mandelic acid has specific rotation of 150. If a sample contains 60% of the R and 40% of its enantiomer, the [alpha] of his solution is.

The compound 2 -Chloro- 3 -methyl- 1 -butanol has the following formula

Draw the structure of the compound : 3-methyl-2-butanol

The specific rotation of a pure enantiomer is +16^@ . The observed rotation, if it is isolated from a reaction with 25% racemisation and 75% inversion is

The specific rotation of a pure enantiomer is +10^(@) . The observed rotation, if it is isolated from a reaction with 30% recemisation and 70% inversion is