If x = 3, y = -2 and z = 1 then `(x -y + z)^2` =

If ( x - 1 )^3 + ( y - 2 )^3 + ( z - 3 )^3 = 3 ( x - 1 ) ( y - 2 ) ( z - 3 ) and x - 1 != y -2 != z-3 , then x + y + z is equal to : ( A ) 2 ( B ) -6 ( C ) 6 ( D ) 4

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

2x + 3y + z = 11, x + 2y + z = 8, x-y + z = 2

8x + y + 2z = 4x + 2y + z = 1x + y + z = 2

Find the equation of the plane passing through the intersection of the planes 3x + 2y - z + 1 = 0 and x + y + z - 2 = 0 and the point (2, 2, 1).

2x-3z + w = 1x-y + 2w = 1-3y + z + w = 1x + y + z = 1

If x + y + z = 12, x^(2) + Y^(2) + z^(2) = 96 and (1)/(x)+(1)/(x)+(1)/(z)= 36 . Then find the value x^(3) + y^(3)+z^(3).

If x,y,z gt 0 and x + y + z = 1, the prove that (2x)/(1 - x) + (2y)/(1 - y) + (2z)/(1 - z) ge 3 .