`int_0^pi (xSinx)/(1+Cos^2x)dx`

int_0^(pi/2) (sinx)/(1+Cos^2x)dx

Prove that int_0^a f(x)dx=int_0^af(a-x)dx , hence evaluate int_0^pi(x sin x)/(1+cos^2 x)dx

Evaluate (i) int_0^pi (x sin x)/(1+cos^2 x) dx Evaluate (ii) int_0^pi (4x sin x)/(1+ cos^2 x) dx

Evaluate the following integral: int_0^pi(xsinx)/(1+sinx)dx

Evaluate: int_0^pi x/(1+cos^2x)dx

I_(1) = int_(0)^(pi)(xsinx)/(1+cos^(2)x)dx, I_(2) = int_(0)^(pi)(x^(2)sinx)/((pi^(2)-3pix+3x^(2))(1+cos^(2)x))dx , then

Evaluate int_(0)^(pi)(xsinx)/((1+cos^(2)x))dx .

int_(0)^( pi)(x)/(1+cos^(2)x)dx=

Evaluate int _(0)^(pi)(x)/(1+ cos^(2)x)dx .

int_0^(pi/2) (dx)/(1+cos x)