Find :

`( Sin^4t + Cos^4t - 1 ) /( Sin^6t + Cos^6t -1 )` =

The value of 3(sin^(4)t+cos^(4)t-1)/(sin^(6)t+cos^(6)t-1) is equal to

x = a (cos t + sin t), y = a (sin t-cos t)

If x = a (cos t + t sin t), y = a (sin t - t cos t), then at t = pi//4,(dy)/(dx)

x=2 cos^2 t, y= 6 sin ^2 t

The distance, from the origin, of the normal to the curve, x = 2 cos t + 2t sin t, y = 2 sin t - 2t "cos t at t" = (pi)/(4) , is :

Locus of centroid of the triangle whose vertices are (a cos t, a sin t), (b sin t, - b cos t) and (1, 0), where is a

The locus of the point represented by x = 3 (cos t + sin t ) , y = 2 ( cos t - sin t ) is

Subtract : 3t ^(4) - 4t ^(3) + 2t ^(2) - 6t + 6 from - 4t ^(4) + 8t ^(3) - 4t ^(2) - 2t + 11

The equation of an FM signal is e = 6 sin (10^(6) t + 4 sin 10^(3) t ) . Then, the modulating frequency is

x=e^t (sin t + cos t ),y=e^t(sin t -cos t)