Position of a particle moving in a straight line is given as y = 3t^3 + t^2 (y in cm and t in second) then find acceleration of particle at t = 2sec

The position of a particle moving in a straight line is given by x=3t^(3)-18t^(2)+36t Here, x is in m and t in second. Then

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

[" If position of particle moving in straight line is "],[" given by "x=(t^(3)-2t+10)m" ,where t is time in "],[" second,then acceleration of particle at "t=1],[" sec is "......]

Position of a particle moving along a straight line is given by x=2t^(2)+t . Find the velocity at t = 2 sec.

The position of a particle moving in a string line is given by x = 3t^(3) - 18 t^(2) + 36 t Here, x is in m and t in second . Then

The position of a particle moving on a straight line depends on time t as x=(t+3)sin (2t)

The displacement of a particle moving along a straight line is given by s=3t^(3)+2t^(2)-10t. find initial velocity and acceleration of particle.

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.