Evaluate `sin^2theta/cos^2theta+1`

Evaluate 2(cos^2theta-sin^2theta)=1

Evaluate : Sin^6theta + Cos^6theta = 1 - k Sin^2theta Cos^2theta , find k

If sin theta=12/13 find the value of (sin^2 theta-cos^2 theta)/(2sin theta cos theta)xx1/(tan^2 theta)

If sin theta=(12)/(13), find the value of (sin^(2)theta-cos^(2)theta)/(2sin theta cos theta)xx(1)/(tan^(2)theta)

If cos theta=(5)/(13), find the value of (sin^(2)theta-cos^(2)theta)/(2sin theta cos theta)xx(1)/(tan^(2)theta)

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

prove that- sin^2theta/cos^2theta+cos^2theta/sin^2theta=1/ (sin^2thetacos^2theta)-2

Find the value of (sin^4theta+cos^4theta)/(1-2sin^2 thetacos ^2 theta)

If tan theta=(12)/(13), evaluate (2sin theta cos theta)/(cos^(2)theta-sin^(2)theta)

If sin^(6)theta+cos^(6) theta-1= lambda sin^(2) theta cos^(2) theta , find the value of lambda .