A particle is moving with uniform acceleration. Its position (x) is given in terms of time (t in s) as X =(5t2+4t+8)m ,then

A particle is moving with uniform acceleration. Its position (x) is given in terms of time (t in s ) as x=(5t^(2)+4t+8) , then Its initial velocity is 8m/s Its velocity at time t=3s is 36m/s Its acceleration is 5m//s^2 Its position at t=2 s is 36 m

A particle starts from origin with uniform acceleration. Its displacement after t seconds is given in meter by the relation x=2+5t+7t^2 . Calculate the magnitude of its a. Initial velocity b. Velocity at t=4s c. Uniform acceleration d. Displacement at t=5s

A particle moving with uniform acceleration passes the point x=2m with velocity 20 m//s at the instant t=0 . Some time later it is observed at the point x=32 m moving with velocity 10 m//s . (a) What is its acceleration? (b) Find its position nd velocity at the instant t=8 s . (c) What is the distance traveled during the interval t=0 to 8s ?

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^4)/4-2t^3+4t^2-7. Find when its velocity is maximum

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle is moving in a straight line. Its displacement at any instant t is given by x = 10 t+ 15 t^(3) , where x is in meters and t is in seconds. Find (i) the average acceleration in the intervasl t = 0 to t = 2s and (ii) instantaneous acceleration at t = 2 s.

A particle moves in a straight line and its position x at time t is given by x^(2)=2+t . Its acceleration is given by :-

A particle is moving along the x-axis with its cordinate with time 't' given by x(t)=10+8t-3t^(2) . Another particle is moving along the y-axis with its coordinate as a function of time given by y(t)= 5-8t^(2) At t=1 s, the speed of the4 second particle as measured in the frame of the first particle is given as sqrtv . Then v (in m//s) is

A particle movesin the X-Y plane with a constasnt acceleration of 1.5 m/s^2 in the direction making an angle of 37^0 with the X-axis.At t=0 the particle is at the orign and its velocity is 8.0 m/s along the X-axis. Find the velocity and the position of the particle at t=4.0 s.