`[[1,-1,1],[2,-3,2],[1,3,-1]][[x],[y],[z]]=[[1],[-1],[1]]`,then `[[x],[y],[z]]` is equal to

If [[1 1 1],[0 1 1],[0 0 1]] [[x],[y],[z]] = [[6],[3],[2]] ,then 2x+y-z=?

Use product [[1,-1, 2],[ 0, 2,-3],[ 3,-2, 4]] [[-2, 0, 1],[ 9, 2,-3],[ 6, 1,-2]] to solve the system of equation: x-y+2z=1 ; 2y-3z=1 ; 3x-2y+4z=2

If x!=0,y!=0,z!=0 and |[1+x,1,1],[1+y,1+2y,1],[1+z,1+z,1+3z]|=0 , then x^(-1)+y^(-1)+z^(-1) is equal to a.1 b.-1 c.-3 d. none of these

Determine the product [[-4, 4, 4], [-7, 1, 3],[5, -3, -1]][[1, -1, 1],[1, -2, -2],[2, 1, 3]] and use it to solve the system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z = 1

Determine the product [[-4, 4, 4], [-7, 1, 3],[5, -3, -1]][[1, -1, 1],[1, -2, -2],[2, 1, 3]] and use it to solve the system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z = 1

if x ne 0 , y ne 0 ,z ne 0 " and " |{:(1+x,,1,,1),(1+y,,1+2y,,1),(1+z,,1+z,,1+3z):}|=0 then x^(-1) +y^(-1) +z^(-1) is equal to

proof |[x,y,z],[x^(2),y^(2),z^(2)],[yz,zx,xy]| = |[1,1,1],[x^(2),y^(2),z^(2)],[x^(3),y^(3),z^(3)]|

If {:[(x+y,y-z),(z-2x,y-x)]:}={:[(3,-1),(1,1)]:} , then

If x!=y!=za n d|[x,x^2, 1+x^3],[y ,y^2 ,1+y^3],[z, z^2, 1+z^3]|=0, then the value of x y z is a. 1 b. 2 c. -1 d. 2

Determine the product [(-4, 4, 4),(-7, 1, 3),( 5,-3,-1)][(1,-1, 1),( 1,-2,-2),( 2, 1, 3)] and use it to solve the system of equations: x-y+z=4,\ \ x-2y-2z=9,\ \ 2x+y+3z=1.