The measured freezing point depression of a non-volatile solute in aqueous solution is `0.20^(@) C.` The elevation in boiting point of the same solution will be [`K_(f)` = 1.86 Km, `k_(b)` = 0.52 K/m]

Options

A. `0.0186`
B. `0.056`
C. ` 0.052 `
D. `5.2 `

Explanation

`Delta T _(f) = K _(f) xx m`
`T _(f):` freezing point of solvent, m - molaliry
`Delta T _(b) = K_(b) xx m`
`K _(f)-` molal depression constant
`(Delta T_(f))/( Delta T _(b)) = (K _(f))/( K _(b)) = ( 0.20)/( Delta T _(b))= ( 1. 86)/(0.52)`
`implies Delta T _(b) = ( 0.20 xx 0.52)/(1.86) = (104)/(1860) = 0.056`