The peak value of current in the circuit when the reading of an ammeter is 4 A is given by

Options

A. `8 A`
B. `4 A`
C. `4 sqrt(2) A`
D. `2 sqrt(2) A`

Explanation

To find the peak value of current (I₀) in the circuit when the reading of an ammeter (I) is 4 A, we can use the relationship between the root mean square (RMS) value and the peak value of alternating current (AC). The formula is:

\[ I = \frac{I₀}{\sqrt{2}} \]

Where:
- I is the RMS current (4 A in this case)
- I₀ is the peak current

### Step-by-Step Solution:

1. **Identify the given value**:
The RMS current (I) is given as 4 A.

2. **Use the formula to find the peak current**:
Rearranging the formula to solve for I₀ gives us:
\[ I₀ = I \times \sqrt{2} \]

3. **Substitute the value of I**:
Substitute I = 4 A into the equation:
\[ I₀ = 4 \times \sqrt{2} \]

4. **Calculate the value**:
Now, calculate the value of \( \sqrt{2} \) (approximately 1.414):
\[ I₀ = 4 \times 1.414 \]
\[ I₀ \approx 5.656 \, \text{A} \]

5. **Final result**:
Therefore, the peak value of current (I₀) is approximately 5.656 A.

### Final Answer:
The peak value of current in the circuit when the reading of an ammeter is 4 A is approximately 5.656 A.