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Find the equation of the straight line ...

Find the equation of the straight line which passes through the point (2, -3) and is perpendicular to the line 2 x + 3y + 5 = 0

A

3 x - 2y - 12 = 0

B

3x + 2y - 12 = 0

C

2 x + 3y = 12

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the straight line that passes through the point (2, -3) and is perpendicular to the line given by the equation \(2x + 3y + 5 = 0\), we can follow these steps: ### Step 1: Find the slope of the given line The equation of the line can be rewritten in slope-intercept form \(y = mx + b\), where \(m\) is the slope. Starting with: \[ 2x + 3y + 5 = 0 \] we can isolate \(y\): \[ 3y = -2x - 5 \] \[ y = -\frac{2}{3}x - \frac{5}{3} \] From this, we can see that the slope \(m_1\) of the given line is \(-\frac{2}{3}\). ### Step 2: Find the slope of the perpendicular line The slope of a line that is perpendicular to another line is the negative reciprocal of the original line's slope. Therefore, if the slope of the given line is \(-\frac{2}{3}\), the slope \(m_2\) of the perpendicular line is: \[ m_2 = -\frac{1}{m_1} = -\frac{1}{-\frac{2}{3}} = \frac{3}{2} \] ### Step 3: Use the point-slope form of the equation of a line The point-slope form of a line's equation is given by: \[ y - y_1 = m(x - x_1) \] where \((x_1, y_1)\) is a point on the line and \(m\) is the slope. Substituting the point \((2, -3)\) and the slope \(\frac{3}{2}\): \[ y - (-3) = \frac{3}{2}(x - 2) \] This simplifies to: \[ y + 3 = \frac{3}{2}(x - 2) \] ### Step 4: Simplify the equation Now, we can distribute and simplify: \[ y + 3 = \frac{3}{2}x - 3 \] Subtracting 3 from both sides gives: \[ y = \frac{3}{2}x - 6 \] ### Step 5: Write the final equation in standard form To convert this to standard form \(Ax + By + C = 0\), we can rearrange it: \[ -\frac{3}{2}x + y + 6 = 0 \] Multiplying through by 2 to eliminate the fraction: \[ -3x + 2y + 12 = 0 \] or rearranging gives: \[ 3x - 2y - 12 = 0 \] Thus, the equation of the straight line that passes through the point (2, -3) and is perpendicular to the line \(2x + 3y + 5 = 0\) is: \[ 3x - 2y - 12 = 0 \]
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