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The equation of a line which passes thro...

The equation of a line which passes through the point (-3, -2) and cuts of negative intercepts in the ratio of 4 : 3 is

A

` 2 x + 9y - 9 = 0 `

B

` 3 x + 4y + 17 = 0 `

C

` x + 2y + 12 = 0`

D

` 2 x + 3y + 11 = 0 `

Text Solution

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The correct Answer is:
To find the equation of a line that passes through the point (-3, -2) and cuts negative intercepts in the ratio of 4:3, we can follow these steps: ### Step 1: Define the Intercepts Let the x-intercept be \( a \) and the y-intercept be \( b \). According to the problem, the ratio of the intercepts is given as: \[ \frac{a}{b} = \frac{4}{3} \] This implies: \[ a = -\frac{4}{3}b \] (Note: The intercepts are negative since the line cuts the axes in the negative quadrant.) ### Step 2: Write the Equation of the Line The equation of a line in terms of its intercepts is given by: \[ \frac{x}{a} + \frac{y}{b} = 1 \] Substituting \( a = -\frac{4}{3}b \) into the equation, we have: \[ \frac{x}{-\frac{4}{3}b} + \frac{y}{b} = 1 \] Multiplying through by \( -\frac{4}{3}b \) to eliminate the denominators: \[ 3x + 4y = -\frac{4}{3}b \] ### Step 3: Substitute the Point (-3, -2) Since the line passes through the point (-3, -2), we substitute \( x = -3 \) and \( y = -2 \) into the equation: \[ 3(-3) + 4(-2) = -\frac{4}{3}b \] Calculating the left side: \[ -9 - 8 = -\frac{4}{3}b \] \[ -17 = -\frac{4}{3}b \] ### Step 4: Solve for \( b \) To find \( b \), we can multiply both sides by -1: \[ 17 = \frac{4}{3}b \] Now, multiply both sides by \( \frac{3}{4} \): \[ b = \frac{3 \times 17}{4} = \frac{51}{4} \] ### Step 5: Find \( a \) Using the value of \( b \) to find \( a \): \[ a = -\frac{4}{3}b = -\frac{4}{3} \times \frac{51}{4} = -\frac{51}{3} \] ### Step 6: Write the Final Equation Now substituting \( a \) and \( b \) back into the equation of the line: \[ \frac{x}{-\frac{51}{3}} + \frac{y}{\frac{51}{4}} = 1 \] Multiplying through by \( -12 \) (the least common multiple of 3 and 4) to clear the denominators: \[ -12 \cdot \frac{x}{-\frac{51}{3}} + 12 \cdot \frac{y}{\frac{51}{4}} = -12 \] This simplifies to: \[ 4x + 3y = -12 \] Rearranging gives: \[ 4x + 3y + 12 = 0 \] ### Final Answer The equation of the line is: \[ 4x + 3y + 12 = 0 \]
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