If `(x+3)/(4)=5` and `(y-2)/(3)=6` then `x` and `y` are:

if (x-y)^3=216 and (x-y)^5=32 , then find x^3-y^3 . The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Therefore, x-y=6 and x+y=2 . (B) Solving x-y=6 and x+y=2rArrx=4, y=-2 . (C) x^3-y^3=64-(-2)^3=64+8=72 (D) (x-y)^3=216rArr(x-y)^3=6^3rArr x-y=6 and (x+y)^5=32rArr (x+y)^5=2^5rArr x+y=2 .

If log_(5)(3^(x)-4^(y))=3 and 3^((x)/(2))-2^(y)=5, then (x)/(y) is equal to

If (2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) then

If x=5 and y=-2 , then find the value of (i) (8x-2y+5)/(2x+4ty+12) " "(ii) (5x-6y-7)/(3x+6y+12)

If 2x+3y=5 and 3x+2y=10 then x-y= (a) 3 (b) 4 (c) 5 (d) 6

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

If r_(1), r_(2) " and " r_(3) are the radii of the circle x^(2) + y^(2) - 4x + 6y = 5 , x^(2) + y^(2) + 6x - 4y = 3 " and " x^(2) + y^(2) - 2x + 4y = 8

The lines 2x+y=3 and 4x+2y= 6 are

If X and Y are two matrices such that X+Y={:[(4,-3),(5,2)]:}andX-Y={:[(6,-5),(3,2)]:} , then find the matrices X and Y.

Simplify: 5 (x + 3y) -2 (3x-4y)