If `A=[[2,1],[1,1]]` and `A^(-1)=[[1,-1],[x,2]]` then `x=`

solve for x, [[x^2,1],[2,x]] + [[2x,2],[-1,2]] = [[-1,3],[1,1]]

If |(3,2),(1,x)|-|(2x,3),(-2,1)|=|(4.1,1),(2,1)|^(2) , then x=______

Let y_1=tan^(-1)((sqrt(1+x^2)-1)/x) and y_2=tan^(-1)((2xsqrt(1-x^2))/(1-2x^2)) then (dy_1)/(dy_2)=

If x_(1) = 2 tan^(-1) ((1 + x)/(1 -x)), x_(2) = sin^(-1) ((1 - x^(2))/(1 + x^(2))), " where " x in (0, 1) , then x_(1) + x_(2) is equal to

If x in[-1/2,1] then sin^(-1)(sqrt(3)/(2)x-1/2sqrt(1-x^(2)))

Statement -1: if -1lexle1 then sin^(-1)(-x)=-sin^(-1)x and cos^(-1)(-x)=pi-cos^(-1)x Statement-2: If -1lexlex then cos^(-1)x=2sin^(-1)sqrt((1-x)/(2))= 2cos^(-1)sqrt((1+x)/(2))

2 tan^(-1) x = sin^(-1) ((2x)/(1+x^(2))) , 1 le x le 1