The applied potential difference in the circuit shown is `V=10sin100t` where V is in volt and t is in second. If the power factor of the circuit is `(1)/(sqrt(2))`,then the value of capacitance C of the circuit,nearly is

The power factor of the circuit in fig. is 1//sqrt(2) . The capacitance of the circuit is equal to

The potential difference V_A - V_B for the circuit shown in fig. is. -(22//x)V. find the value of x.

In the circuit shown, what is the potential difference V_(PQ) in volts ?

In the circuit shown in fin. Calculate the capacitance C of the capacitor, if the power factor of the circuit is unity. Also, calculate Q factor of the circuit.

In an electric circuit applied ac emf is e=20 sin 300t volt and the current is i=4 sin 300t ampere. The reactance of the circuit is-

The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit. The power factor of this circuit is

In an AC circuit, the applied potential difference and the current flowing are given by V=20sin100t volt , I=5sin(100t-pi/2) amp The power consumption is equal to

In the circuit shown, what is the potential different V_(PQ) ?

A circuit draws a power of 550 watt from a source of 220 volt, 50 Hz . The power factor of the circuit is 0.8 and the current lags in phase behind the potential difference. To make the power factor of the circuit as 1.0, The capacitance should be connected in series with it is

In the circuit shown in figure, circuit is closed at time t=0 . At time t=ln(2) second