the radius of curvature for a projectile motion horizontal ground is minimum when the instantaneous velocity vector makes an angle a with the horizontal where a will be is

What is the radius of curvature of the parabola traced out by the projectile in which a particle is projected with a speed u at an angle theta with the horizontal, at a point where the velocity of particle makes an angle theta//2 with the horizontal.

What is the radius of curvature of the parabola traced out by the projectile in the previous problem projected with speed v at an angle of theta with the horizontal at a point where the particle velocity makes an angle theta/2 with the horizontal?

A body is projected at an angle 60^@ with horizontal with kinetic energy K. When the velocity makes an angle 30^@ with the horizontal, the kinetic energy of the body will be

What is the radius of curvature of the parabola traced out by the projectile in which a particle is projected by a speed u at an angle 'theta' with the horizontal, at a point where the particle velocity makes and angle theta/2 with the horizontal?

A projectile is thrown with a velocity of 20 m//s, at an angle of 60^(@) with the horizontal. After how much time the velocity vector will make an angle of 45^(@) with the horizontal (in upward direction) is (take g= 10m//s^(2))-

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains g in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path Consider that a particle is projected with velocity u=10 m//s at an angle theta=60^(@) with the horizontal and take value of g=10m//s^(2) . Now answer the following questions. The radius of curvature of path of particle at the instant when the velocity vector of the particle becomes perpendicular to initial velocity vector is

A particle of mass m is projected with velocity u at an angle alpha with horizontal. During the period when the particle descends from highest point to the position where its velocity vector makes an angle (alpha)/(2) with horizontal. Work done by gravity force is

A projectile is fired with a speed u at an angle theta with the horizontal. Find its speed when its direction of motion makes an angle alpha with the horizontal.

A projectile is fired with a speed u at an angle theta with the horizontal. Find its speed when its direcrtion of motion makes an angle alpha with the horizontal.

A projectile is projected from the ground by making an angle of 60^@ with the horizontal. After 1 s projectile makes an angle of 30^@ with the horizontal . The maximum height attained by the projectile is (Take g=10 ms^-2)