Balance the following reaction by ion electron method.
`Cr_(2)O_(7)^(-2)+SO_(3)^(-2)` `rightarrow Cr^(3+)+SO_(4)^(-2)`

[" 12,Balance the following redox reaction by ion - electron method: "],[Cr_(2)O_(7)d(aq)+SO_(2)(q)rarr Cr^(3+)(aq)+SO_(4)^(2)(aq)" (acidic medium) "]

Cr_(2)O_(7)^(2-)+H^(+)+SO_(3)^(2-) to Cr^(3+)(aq.)+SO_(4)^(2-)

Balancing the following redox reactions by ion-electron method. \(MnO_{4}^{-1}+SO_{2} (g) \rightarrow Mn^{2+}+HSO_{4}^{-}\) ( in Acid medium )

Balance the following rebox reactions by ion electron method: a. MnO_(4)^(Θ)(aq)+I^(Θ)(aq) rarr MnO_(2)(s)+I_(2)(s) (in basic medium) b. MnO_(4)^(Θ)(aq)+SO_(2)(g) rarr Mn^(2+)(aq)+HSO_(4)^(Θ)(aq) (in acidic solution) c. H_(2)O_(2)(aq)+Fe^(2+)(aq) rarr Fe^(3+)(aq)+H_(2)O(l) (in acidic solution) d. Cr_(2)O_(7)^(2-)+SO_(2)(g) rarr Cr^(3+)(aq)+SO_(4)^(2-)(aq) (in acidic solution)

Balance the following equation by oxidation number method: K_(2)Cr_(2)O_(7)+FeSO_(4)+H_(2)SO_(4)=Cr_(2)(SO_(4))_(3)+Fe_(2)(SO_(4))+K_(2)SO_(4)+H_(2)O

Balance the following reaction by oxidation number and ion electron method: KMnO_(4)+H_(2)SO_(4)+K_(2)C_(2)O_(4)rarrMnSO_(4)+CO_(2)+K_(2)SO_(4)

Balance the equation by lon-electron method (ix) Cr_(2)O_(7)^(2-) + Fe^(2+) to Fe^(3+) +Cr^(3+) (In acidic medium)