Two identical equi- concave lenses made of glass of refractive index `1.5` placed in contact has power `P`. When a liquid of refractive index `mu` is filled in the gap between the concave lenses,the power becomes `(P/3)`.The value of `mu` is `(R)/(2)`.Find `K`.

Two identical equi-concave lenses made of magnitude of combined glass of refractive index 1.5, placed in contact has magnitude of combined power p. when a liquid of refractive index mu is filled in the gap between the concave lenses, the power becomes +p/3 . the value of mu is K/3 . find the value of K

A lens is made of flint glass (refractive index =1.5 ). When the lens is immersed in a liquid of refractive index 1.25 , the focal length:

A plano-concave lens is made of glass of refractive index 1.5 and the radius of curvature of its curved face is 100 cm. What is the power of the lens?

A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a

When a lens of power P (in air) made of material of refractive index mu is immersed in liquid of refractive index mu_(0) Then the power of lens is:

A convex lens of refractive index 3/2 has a power of 2.5^(@) . If it is placed in a liqud of refractive index 2,the new power of the lens is

Find focal lengths of lenses made of glass (mu=3//2) and placed in air.

An equiconvex lens is made from glass of refractive index 1.5. If the radius of each surface is changed from 5cm to 6cm, then the power

A thin equi-convex lens is made of glass of refractive index 1.5 and its length is 0.2 m. If it acts as a concave lens of 0.5 m focal length when dipped in a liquid, the refractive index of the liquid is

A thin glass (refractive index 1.5) lens has optical power of -5D in air. Its optical power in a liquid medium with refractive index 1.6 will be