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97.Transverse velocity...

97.Transverse velocity

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At t=0,a transverse wave pulse travelling in the positive x direction with a speed of 2 m//s in a wire is described by the function y=6//x^(2) given that x!=0 . Transverse velocity of a particle at x=2 m and t= 2 s is

At t=0,a transverse wave pulse travelling in the positive x direction with a speed of 2 m//s in a wire is described by the function y=6//x^(2) given that x!=0 . Transverse velocity of a particle at x=2 m and t= 2 s is

A transverse wave travelling in a string produce maximum transverse velocity of 3 m//s and maximum transverse acceleration 90 m//s^(2) in a particle. If the velocity of wave in the string is 20 m//s . Datermine the equation of the wave ?

The maximum transverse velocity and maximum transverse acceleration of a harmonic wave in a one - dimensional string are 1 ms^(-1) and 1 ms^(-2) respectively. The phase velocity of the wave is 1 ms^(-1) . The waveform is

A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive x direction. The transverse velocity of the particle at x=0 as a function of time is shown. The amplitude of the motion is:

A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive x direction. The transverse velocity of the particle at x=0 as a function of time is shown. The amplitude of the motion is:

A string of mass 0.2 kg/m and length l= 0.6 m is fixed at both ends and stretched such that it has a tension of 80 N. the string vibrates in 3 segments with maximum amplitude of 0.5 cm. the maximum transverse velocity amplitude is

A wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart.The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.300 cm. (a) What is the speed of propagation of transverse wave in the wire? Compute the tension in the wire. (c) Find the maximum transverse velocity and acceleration of particles in the wire.

A pulse is started at a time t=0 along the +x direction on a long, taut string. The shape of the pulse at t=0 is given by function f(x) with here f and x are in centimeters. The linear mass density of the string is 50 g//m and it is under a tension of 5N . The transverse velocity of the particle at x=13 cm and t=0.015 s will be

A pulse is started at a time t = 0 along the +x directions an a long, taut string. The shaot of the puise at t = 0 is given by funcation y with y = {{:((x)/(4)+1fo r-4ltxle0),(-x+1fo r0ltxlt1),("0 otherwise"):} here y and x are in centimeters. The linear mass density of the string is 50 g//m and it is under a tension of 5N , The transverse velocity of the particle at x = 13 cm and t = 0.015 s will be