If `(5x)/4 +(6-x)/8 = (6(x+3))/3-1/6 ` then x = ?

If (3x)/((x-6)(x+a))=2/(x-6)+1/(x+a) " then "a=

Solve (6x+1)/3 + 1=(x-3)/6

If (x-2)/3=(2x-1)/3-1, then x= (a) 2 (b) 4 (c) 6 (d) 8

Solve : (2x)/(3)-(x-1)/(6)+(7x-1)/(4)=2(1)/(6) . Hence, find the value of 'a', if (1)/(a)+5x=8 .

If the median of the data x_(1), x_(2), x_(3), x_(4), x_(5),x_(6), x_(7), x_(8) " is " alpha and x_(1) lt x_(2) lt x_(3) lt x_(4) lt x_(5) lt x_(6) lt x_(7) lt x_(8) , then the median of x_(3), x_(4), x_(5), x_(6) is

Solve: ((5x-3))/6-((2x-1))/3=((4-3x))/2

x+7-(8x)/(3)=(17)/(6)-(5x)/(2)

if 6sin^(-1)(x^2 -6x + 8.5)=pi then

If int(x^(9)+x^(6)+x^(3))(2x^(6)+3x^(3)+6)^(1//3)dx=a(2x^(9)+3x^(6)+6x^(3))^(4//3)+c then the value of 48a must be _______

If x = (1.3)/(3.6) + (1.3.5)/(3.6.9) + (1.3.5.7)/(3.6.9.12) + ….. then prove that 9x^2 + 24x = 11