(1) `-3+8=...`
(2) `2/6+3/6=(...+...)/6=(...)/`

Add: 3/8+1/2 (ii) 1/6+3/8

(1)/(2.4)+(1.3)/(2.4.6)+(1.3.5)/(2.4.6.8)+(1.3.5.7)/(2.4.6.8*10)+....oo is equal to

Simplify the following ratios: (a) 1/6:1/8 (2) 2 1/3 : 3 1/2 c. 5/6: 3/8: 3 3/4

8^(7)xx2^(6)-:8^(2.4)=8^(?) a.6.6b.8.6c.9.6d.10.6

(2)/(3)+-(6)/(8)+(-(3)/(10))

Arrange the following fractions in ascending order: 3/8,5/6,6/8,2/4,1/3 (ii) 4/6,3/8,6/(12),5/(16)

Comprehension 2 In comparison of two numbers, logarithm of smaller number is smaller, if base of the logarithm is greater than one. Logarithm of smaller number is larger, if base of logarithm is in between zero and one. For example log_2 4 is smaller than (log)_2 8 a n d(log)_(1/2)4 is larger than (log)_(1/2)8. Identify the correct order: (log)_2 6 (log)_3 8> log_3 6>(log)_4 6 (log)_3 8>(log)_2 6> log_3 6>(log)_4 6 (log)_2 8<(log)_4 6

The value of the infinite product 6(1)/(2)xx6^((2)/(4))xx6^((3)/(8))xx6(4)/(16)xx...