Let `f(x)=int(dx)/((x^(2)+1)(x^(2)+9))` and `f(0)=0` if `f(sqrt(3))` `=(5)/(36)k,` then `k` is

Let f(x)=int x^2/((1+x^2)(1+sqrt(1+x^2)))dx and f(0)=0 then f(1) is

Let f(x)=int(x^2dx)/((1+x^2)(1+sqrt(x^2+1)))a n df(0)=0. Then value of f(1) will be

If f(x)=int(3x^4-1)/(x^4+x+1)^2dx and f(0)=0 , then f(-1)= …

Let int(dx)/((x^(2)+1)(x^(2)+9))=f(x)+C, (where C is constant of integration) such that f(0)= 0.If f(sqrt(3))=(5)/(36)k, then k is

Let int(dx)/((x^(2)+1)(x^(2)+9))=f(x)+C, (where C is constant of integration) such that f(0)= 0.If f(sqrt(3))=(5)/(36)k, then k is

Let f(x) =int_(0)^(x) |xx-2|dx, ge 0 . Then, f'(x) is

Let f(x+y)+f(x-y)=2f(x)f(y) AA x,y in R and f(0)=k , then

Let int((1+x^4)dx)/((1-x^4)^(3/2))=f(x)+C_(1) where f(0)=0 and int\ f(x)dx=g(x)+C_(2) with g(0)=0 . If g((1)/(sqrt2))=(pi)/(k) . Find k .

If f(x) = int(5x^(8)+7x^(6))/((x^(2)+1+2x^(7))^(2))dx, (x ge 0) , and f(0) = 0, then the value of f(1) is

If f(x)=int_a^x[f(x)]^(-1)dx and int_a^1[f(x)]^(-1)dx=sqrt(2) , then