`I=int(dx)/(2+cos x-sin x)`

int(dx)/(cos x(sin x+2))

int (cos^(2)x+sin 2x)/((2 cos x- sin x)^(2))dx

(i) int e^(x). "[log (sec x+tan x) + sec x dx " (ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx

The value of int_(0)^(2pi) |cos x -sin x|dx is

I=int(sin^2x)/(1+cos x)dx

int(1)/(3+2 sin x +cos x)dx

int(sin2x)/(cos x)*dx

If I_(1)=int_(0)^(pi//2) cos(sin x) dx,I_(2)=int_(0)^(pi//2) sin (cos x) dx and I_(3)=int_(0)^(pi//2) cos x dx then

int(sin x+x cos x)/(x sin x)dx

int(2-3 cos x)/(sin^(2) x)dx