A certain sum is divided between Ram and Mohan in the ratio 14:9. Ram gets Rs 3265 more than that of Mohan. Find the sum

Options

A. Rs 15019
B. Rs 15109
C. Rs 16019
D. Rs 10619

Answer

To solve the problem, we need to find the total sum of money that is divided between Ram and Mohan in the ratio of 14:9, given that Ram receives Rs 3265 more than Mohan.

### Step-by-Step Solution:

1. **Understanding the Ratio**:
- The ratio of the amounts received by Ram and Mohan is given as 14:9.
- Let the amount received by Ram be \( 14x \) and the amount received by Mohan be \( 9x \), where \( x \) is a common multiplier.

2. **Setting Up the Equation**:
- According to the problem, Ram gets Rs 3265 more than Mohan. Therefore, we can set up the equation:
\[ 14x = 9x + 3265 \]

3. **Solving for \( x \)**:
- Rearranging the equation:
\[ 14x - 9x = 3265 \]
\[ 5x = 3265 \]
- Now, divide both sides by 5 to find \( x \):
\[ x = \frac{3265}{5} = 653 \]

4. **Calculating the Amounts**:
- Now that we have \( x \), we can find the amounts received by Ram and Mohan:
- Amount received by Ram:
\[ 14x = 14 \times 653 = 9142 \]
- Amount received by Mohan:
\[ 9x = 9 \times 653 = 5877 \]

5. **Finding the Total Sum**:
- The total sum of money is the sum of the amounts received by Ram and Mohan:
\[ \text{Total Sum} = 14x + 9x = 23x \]
- Now substituting the value of \( x \):
\[ \text{Total Sum} = 23 \times 653 = 15019 \]

### Final Answer:
The total sum of money is Rs 15,019.