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32*4^?=2048...

`32*4^?=2048`

A

3

B

7

C

1

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \(32 \times 4^? = 2048\), we can follow these steps: ### Step 1: Express the numbers as powers of 2 First, we need to express 32, 4, and 2048 in terms of powers of 2. - \(32 = 2^5\) - \(4 = 2^2\) - \(2048 = 2^{11}\) ### Step 2: Rewrite the equation Now we can rewrite the original equation using these expressions: \[ 2^5 \times (2^2)^? = 2^{11} \] ### Step 3: Simplify the equation Using the property of exponents \((a^m)^n = a^{m \cdot n}\), we can simplify the left side: \[ 2^5 \times 2^{2?} = 2^{11} \] ### Step 4: Combine the exponents Since the bases are the same, we can add the exponents: \[ 2^{5 + 2?} = 2^{11} \] ### Step 5: Set the exponents equal to each other Now, we can set the exponents equal to each other: \[ 5 + 2? = 11 \] ### Step 6: Solve for ? Subtract 5 from both sides: \[ 2? = 11 - 5 \] \[ 2? = 6 \] Now, divide both sides by 2: \[ ? = \frac{6}{2} = 3 \] ### Conclusion The value of the question mark is \(3\).
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