3/9 * 2286 + 2/11 * 1397 = ?

Options

A. 916
B. 1016
C. 1216
D. 1026

Answer

To solve the equation \( \frac{3}{9} \times 2286 + \frac{2}{11} \times 1397 \), we will follow these steps:

### Step 1: Simplify the fractions
First, we simplify the fractions \( \frac{3}{9} \) and \( \frac{2}{11} \).

- \( \frac{3}{9} = \frac{1}{3} \)
- \( \frac{2}{11} \) is already in its simplest form.

### Step 2: Multiply the simplified fractions by their respective numbers
Now we will multiply each fraction by the respective number.

1. For \( \frac{1}{3} \times 2286 \):
\[ \frac{1}{3} \times 2286 = \frac{2286}{3} \]
To calculate \( \frac{2286}{3} \):
\[ 2286 \div 3 = 762 \]

2. For \( \frac{2}{11} \times 1397 \):
\[ \frac{2}{11} \times 1397 = \frac{2 \times 1397}{11} = \frac{2794}{11} \]
To calculate \( \frac{2794}{11} \):
\[ 2794 \div 11 = 254 \]

### Step 3: Add the results from Step 2
Now we add the two results together:
\[ 762 + 254 = 1016 \]

### Final Answer
Thus, the value of \( \frac{3}{9} \times 2286 + \frac{2}{11} \times 1397 \) is \( 1016 \).