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The milk and water in two vessels A and ...

The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel C consisting half milk and half water?

A

`8:3`

B

`7:5`

C

`4:3`

D

`2:3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the ratio in which the liquids from vessels A and B should be mixed to obtain a new mixture in vessel C that consists of half milk and half water. ### Step 1: Understand the ratios in vessels A and B - In vessel A, the ratio of milk to water is 4:3. This means: - Milk in A = 4 parts - Water in A = 3 parts - Total parts in A = 4 + 3 = 7 parts - In vessel B, the ratio of milk to water is 2:3. This means: - Milk in B = 2 parts - Water in B = 3 parts - Total parts in B = 2 + 3 = 5 parts ### Step 2: Calculate the fractions of milk and water in each vessel - In vessel A: - Fraction of milk = 4/7 - Fraction of water = 3/7 - In vessel B: - Fraction of milk = 2/5 - Fraction of water = 3/5 ### Step 3: Set up the desired mixture in vessel C We want vessel C to have a mixture that is half milk and half water, which can be represented as: - Fraction of milk in C = 1/2 - Fraction of water in C = 1/2 ### Step 4: Use the method of allegations To find the ratio in which the two vessels should be mixed, we can use the method of allegations. 1. **Calculate the difference for water:** - Water in A = 3/7 - Water in B = 3/5 - Water in C = 1/2 Using the formula: \[ \text{Difference for A} = \text{Water in A} - \text{Water in C} = \frac{3}{7} - \frac{1}{2} = \frac{6 - 7}{14} = -\frac{1}{14} \] (We take the absolute value for the purpose of ratio.) \[ \text{Difference for B} = \text{Water in C} - \text{Water in B} = \frac{1}{2} - \frac{3}{5} = \frac{5 - 6}{10} = -\frac{1}{10} \] (Again, we take the absolute value.) 2. **Set up the ratio:** The ratio of the differences gives us the ratio in which to mix A and B: \[ \text{Ratio} = \frac{1/10}{1/14} = \frac{14}{10} = \frac{7}{5} \] ### Final Answer The liquids in both vessels A and B should be mixed in the ratio of **7:5** to obtain a new mixture in vessel C consisting of half milk and half water.
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