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A bag contains Rs 216 in the form of 1 R...

A bag contains Rs 216 in the form of 1 Re, 50 paise and 25 paise coins in the ratio of 2:3:4. The number of 50 paise coins is

A

140

B

175

C

184

D

144

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Understand the Ratios The coins are in the ratio of 1 Rupee : 50 Paise : 25 Paise = 2 : 3 : 4. Let's denote the number of 1 Rupee coins as 2x, the number of 50 Paise coins as 3x, and the number of 25 Paise coins as 4x. ### Step 2: Calculate the Total Value of Each Coin Type - The value of 1 Rupee coins (2x coins) = 2x * 1 = 2x Rupees - The value of 50 Paise coins (3x coins) = 3x * 0.50 = 1.5x Rupees - The value of 25 Paise coins (4x coins) = 4x * 0.25 = 1x Rupees ### Step 3: Write the Total Value Equation The total value of all coins is given as Rs 216. Therefore, we can write the equation: \[ 2x + 1.5x + 1x = 216 \] ### Step 4: Combine Like Terms Combine the terms on the left side: \[ (2x + 1.5x + 1x) = 4.5x \] So the equation becomes: \[ 4.5x = 216 \] ### Step 5: Solve for x To find the value of x, divide both sides by 4.5: \[ x = \frac{216}{4.5} = 48 \] ### Step 6: Find the Number of 50 Paise Coins The number of 50 Paise coins is represented by 3x. Therefore: \[ \text{Number of 50 Paise coins} = 3x = 3 \times 48 = 144 \] ### Conclusion The number of 50 Paise coins is **144**.
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